A) \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{2}}OH\]
B) \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}OH\]
C) \[C{{H}_{3}}C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}\]
D) \[C{{H}_{3}}{{(C{{H}_{2}})}_{3}}-C{{H}_{2}}OH\]
Correct Answer: C
Solution :
2-butanol exists in optically active forms due to the presence of asymmetric carbon atom \[C{{H}_{3}}C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{{{C}^{*}}}}}\,-C{{H}_{3}}\] \[{{C}^{*}}=\]asymmetric carbon atom.
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