RAJASTHAN ­ PET Rajasthan PET Solved Paper-2006

  • question_answer
    In ideal condition, the number of moles of oxygen in 1 L air which has 21% oxygen according to volume

    A)  2.10 mol        

    B)  0.0093 mol

    C)  0.186 mol       

    D)  0.210 mol

    Correct Answer: B

    Solution :

     \[\because \]Volume of\[{{O}_{2}}\]in one litre air\[=\frac{21}{100}\times 1000\] \[=210mL\] \[\therefore \]Number of moles of\[{{O}_{2}}\]in 1 L \[=\frac{210}{22400}=0.0093\]


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