question_answer

Alkene\[R-CH=C{{H}_{2}}\]reacts with\[{{B}_{2}}{{H}_{6}}\]to give a product. The oxidation of product by alkaline hydrogen peroxide to form

A)  \[R-\underset{\begin{smallmatrix}  || \\  O \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\]

B)  \[R-\underset{\begin{smallmatrix}  | \\  OH \end{smallmatrix}}{\mathop{C}}\,-\underset{\begin{smallmatrix}  | \\  OH \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,\]

C)  \[R-C{{H}_{2}}-CHO\]

D)  \[R-C{{H}_{2}}-C{{H}_{2}}-OH\]

Correct Answer: D

Solution :

 \[\underset{alkene}{\mathop{3R-CH=C{{H}_{2}}}}\,+\underset{diborane}{\mathop{{{B}_{2}}{{H}_{6}}}}\,\xrightarrow[{}]{{}}\] \[{{(R-C{{H}_{2}}-C{{H}_{2}})}_{3}}B\]            \[R-C{{H}_{2}}-C{{H}_{2}}OH\]