RAJASTHAN ­ PET Rajasthan PET Solved Paper-2007

  • question_answer
    The uncertainty in the momentum of a particle is\[{{10}^{-30}}kg-m/s\]. The minimum uncertainty in its position will be

    A)  \[{{10}^{-8}}m\] 

    B)  \[{{10}^{-12}}m\]

    C)  \[{{10}^{-16}}m\]        

    D)  \[{{10}^{-4}}m\]

    Correct Answer: D

    Solution :

     \[\Delta p\,\Delta x\ge h\] \[\Delta x=\frac{h}{\Delta p}\] \[=\frac{1.034\times {{10}^{-34}}}{{{10}^{-30}}}={{10}^{-4}}m\]


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