RAJASTHAN ­ PET Rajasthan PET Solved Paper-2007

  • question_answer
    The power dissipated across resistance R which is connected across a battery of potential V is P. If resistance is doubled, then the power becomes

    A)  1/2              

    B)  2

    C)  1/4              

    D)  2

    Correct Answer: A

    Solution :

     Electric power \[P=\frac{{{V}^{2}}}{R}\] or            \[P\propto \frac{1}{R}\] or \[\frac{{{P}_{2}}}{{{P}_{1}}}=\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{R}{2R}\] \[{{P}_{2}}=\frac{P}{2}\]


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