RAJASTHAN ­ PET Rajasthan PET Solved Paper-2007

  • question_answer
    If acceleration of a particle at any time is given by \[a=2t+5\] Calculate, the velocity after 5s, if it starts from rest.

    A)  50 m/s            

    B)  25 m/s

    C)  100 m/s          

    D)  75 m/s

    Correct Answer: A

    Solution :

     Acceleration, \[a=2t+5\] \[\frac{dv}{dt}=2t+5\] \[dv=(2t+5)dt\]              ...(i) Integrating Eq. (i) both sides within the limits \[\int_{0}^{v}{dv}=\int_{0}^{5}{(2t+5)}dt\] \[v=\left[ \frac{2{{t}^{2}}}{2}+5t \right]_{0}^{5}\] \[=[5\times 5+5\times 5]\] \[v=50m/s\]


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