A) \[{{h}_{1}}={{e}^{2}}h\]
B) \[{{h}_{1}}={{e}^{4}}h\]
C) \[{{h}_{1}}=eh\]
D) \[{{h}_{1}}=h/e\]
Correct Answer: A
Solution :
When a body falls from a height A, it strikes the ground with a velocity\[u=\sqrt{2gh}\]. Therefore, \[v=\sqrt{2gh}\] \[e=\frac{v}{u}=\sqrt{\frac{{{h}_{1}}}{h}}\] \[{{h}_{1}}={{e}^{2}}h\]
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