A) \[A\to .B\to =1\]
B) \[A\to \times B\to =0\]
C) \[A\to .B\to =0\]
D) \[A\to \times B\to =AB\]
Correct Answer: C
Solution :
If there are two vectors\[\overrightarrow{A}\]and \[\overrightarrow{B}\]having angle \[\theta \]between them, then their scalar product \[\overrightarrow{A}.\overrightarrow{B}\]is written as \[\overrightarrow{A}.\overrightarrow{B}=AB\cos \theta \] Scalar product of two vectors will be minimum when\[|\cos \theta |=\min =0,\]ie \[\theta =90{}^\circ \] \[\therefore \] \[{{(\overrightarrow{A}.\overrightarrow{B})}_{\min }}=0\]
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