A) 2
B) 1
C) 3
D) 4
Correct Answer: C
Solution :
\[Ca\xrightarrow[{}]{{}}C{{a}^{2+}}+2{{e}^{-}}\] ?..(i) \[A{{l}^{3+}}+3{{e}^{-}}\xrightarrow[{}]{{}}Al\] ?.(ii) Equation (i) is multiplied by 3 and equation (ii) is multiplied by 2 and then add the both equation. \[3Ca\xrightarrow[{}]{{}}3C{{a}^{2+}}+6{{e}^{-}}\] \[\underline{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2A{{l}^{3+}}+6{{e}^{-}}\xrightarrow[{}]{{}}2Al}\] \[3Ca+2A{{l}^{3+}}\xrightarrow{{}}3C{{a}^{2+}}+2Al\] Hence, the stoichiometry coefficient of\[Ca\]is 3 in the above equation.
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