A) \[C{{O}_{2}}\]
B) \[^{14}C{{O}_{2}}\]
C) CO
D) None of these
Correct Answer: A
Solution :
Benzoic acid reacts with sodium carbonate to give sodium benzoate,\[C{{O}_{2}}\]and water. \[{{C}_{6}}{{H}_{5}}^{14}COOH+N{{a}_{2}}C{{O}_{3}}\xrightarrow[{}]{\Delta }\] \[{{C}_{6}}{{H}_{5}}^{14}COONa+C{{O}_{2}}+{{H}_{2}}O\]
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