A) 1 / 2
B) 1 / 16
C) 1 / 8
D) 1 / 32
Correct Answer: D
Solution :
We know that \[n=\frac{t}{T}\] Given, \[t=3000\text{ }yr\] \[T=600\text{ }yr\] \[n=\frac{3000}{600}=5\] Then, \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}\] \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{5}}=\frac{1}{32}\]
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