A) \[{{N}^{3-}}>{{O}^{2-}}>{{F}^{-}}>N{{a}^{+}}\]
B) \[{{N}^{3-}}>N{{a}^{+}}>{{O}^{2-}}>{{F}^{-}}\]
C) \[N{{a}^{+}}>{{O}^{2-}}>{{N}^{3-}}>{{F}^{-}}\]
D) \[N{{a}^{+}}>{{F}^{-}}>{{O}^{2-}}>{{N}^{3-}}\]
Correct Answer: A
Solution :
The ionic radius ofisoelectronic ions increases with the increasing of negative charge on them and the size of cation is always smaller than the anion. Hence, the decreasing order of ionic radius of ions is as \[{{N}^{3-}}>{{O}^{2-}}>{{F}^{-}}>N{{a}^{+}}\]
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