RAJASTHAN ­ PET Rajasthan PET Solved Paper-2009

  • question_answer
    A black body at a temperature of 2600 K has the wavelength corresponding to maximum emission 1200\[\overset{o}{\mathop{\text{A}}}\,\]. Assuming the moon to be perfectly black body the temperature of the moon, if the wavelength corresponding to maximum emission is 5000\[\overset{o}{\mathop{\text{A}}}\,\] is

    A)  7800 K          

    B)  6240 K

    C)  5240 K          

    D)  3640 K

    Correct Answer: B

    Solution :

     From Wien law \[{{\lambda }_{1}}{{T}_{1}}={{\lambda }_{2}}{{T}_{2}}\] \[{{T}_{2}}=\frac{{{\lambda }_{1}}{{T}_{1}}}{{{\lambda }_{2}}}\] \[=\frac{12000\times 2600}{5000}\] \[{{T}_{2}}=6240K\]


You need to login to perform this action.
You will be redirected in 3 sec spinner