RAJASTHAN ­ PET Rajasthan PET Solved Paper-2009

  • question_answer
    A heater coil cut into two equal parts and one part is connected with heater. Now heat generated in heater will be

    A)  twice            

    B)  half

    C)  one- fourth        

    D)  four times

    Correct Answer: C

    Solution :

     Heat,             \[H={{i}^{2}}Rt\]    ...(i) Where            \[r=\frac{R}{2}\] Then, Heat   \[H'={{i}^{2}}\frac{R}{2}t\] From Eq. (i)   \[H'=\frac{1}{2}H\]


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