A) \[\frac{7}{5}M{{R}^{2}}\]
B) \[\frac{4}{5}M{{R}^{2}}\]
C) \[\frac{2}{5}M{{R}^{2}}\]
D) \[\frac{1}{2}M{{R}^{2}}\]
Correct Answer: A
Solution :
Moment of inertia of the solid sphere of mass M and radius R about is tangent \[I={{I}_{0}}+M{{R}^{2}}\] (According to theorem of parallel axis) \[=\frac{2}{5}M{{R}^{2}}+M{{R}^{2}}\] \[\left( \because {{I}_{0}}=\frac{2}{5}M{{R}^{2}} \right)\] \[I=\frac{7}{5}M{{R}^{2}}\]
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