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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2009

  • question_answer
    68 g sugar\[({{C}_{12}}{{H}_{22}}{{O}_{11}})\]is dissolved in 1 kg of water. What is the mole fraction of sugar?

    A)  0.018            

    B)  0.036

    C)  0.0018           

    D)  0.0036

    Correct Answer: D

    Solution :

     Number of moles of sugar \[=\frac{68}{342}=0.1988\] (\[\because \]Molecular weight of sugar\[=342\]) Number of moles of water\[=\frac{1000}{18}\] \[=55.55\] (\[\because \]Molecular weight of water =18) \[\therefore \]Mole fraction of sugar\[=\frac{0.1988}{0.1988+55.55}\] \[=0.00356\approx 0.0036\]


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