A) 4
B) 5
C) 7
D) 9
Correct Answer: B
Solution :
\[\int_{0}^{4}{|x-1|dx=\int_{0}^{1}{(1-x)dx+\int_{1}^{4}{(x-1)dx}}}\] \[=\left[ x-\frac{{{x}^{2}}}{2} \right]_{0}^{1}+\left[ \frac{{{x}^{2}}}{2}-x \right]_{1}^{4}\] \[=1-\frac{1}{2}+\left[ 8-4-\left( \frac{1}{2}-1 \right) \right]\] \[=\frac{1}{2}+4+\frac{1}{2}=5\]
You need to login to perform this action.
You will be redirected in
3 sec
