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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2010

  • question_answer
    If two waves of same frequency and same amplitude respectively, are superimposed on each other produces a resultant disturbance of the same amplitude, then the waves differ in phase by

    A)  \[\pi \]                 

    B)  2\[\pi \]/3

    C)  \[\pi \]/2                 

    D)  zero

    Correct Answer: D

    Solution :

     \[{{A}^{2}}={{A}^{2}}+{{A}^{2}}+2{{A}^{2}}cos\theta \] \[\Rightarrow \] \[\cos \theta =\frac{1}{2}\] \[\theta =\frac{2\pi }{3}\]


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