A) \[1\]
B) \[\sqrt{\frac{2{{m}_{e}}}{{{m}_{\alpha }}}}\]
C) \[\sqrt{\frac{{{m}_{e}}}{{{m}_{\alpha }}}}\]
D) \[\sqrt{\frac{{{m}_{e}}}{2{{m}_{\alpha }}}}\]
Correct Answer: D
Solution :
Momentum, \[p=mv\] and \[F=\sqrt{\frac{2QV}{m}}\] \[\Rightarrow \] \[p=\sqrt{2QmV}\] \[p\propto \sqrt{Qm}\] \[\therefore \] \[\frac{{{p}_{e}}}{{{p}_{\alpha }}}=\sqrt{\frac{e{{m}_{e}}}{2e{{m}_{\alpha }}}}=\sqrt{\frac{{{m}_{e}}}{2{{m}_{\alpha }}}}\]
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