RAJASTHAN ­ PET Rajasthan PET Solved Paper-2010

  • question_answer
    If half-life of radium is 77 days. Its decay constant in day will be

    A)  \[3\times {{10}^{-3}}/day\]     

    B)  \[9\times {{10}^{-3}}/day\]

    C)  \[1\times {{10}^{-3}}/day\]      

    D)  \[6\times {{10}^{-3}}/day\]

    Correct Answer: C

    Solution :

     Decay constant, \[\lambda =\frac{0.693}{{{T}_{1/2}}}=\frac{0.693}{77}\] \[=9\times {{10}^{-3}}/day\]


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