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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2010

  • question_answer
    The position\[x\]of a particle varies with time t as\[x=a{{t}^{2}}b{{t}^{3}}\].The  acceleration  of the particle will be zero at time t equal to

    A)  \[\frac{a}{b}\]

    B)  \[\frac{2a}{3b}\]

    C)  \[\frac{a}{3b}\]

    D)  \[zero\]

    Correct Answer: C

    Solution :

     Velocity,    \[v=\frac{{{d}^{2}}x}{dt}=2at-3b{{t}^{2}}\] Acceleration, \[a=\frac{{{d}^{2}}x}{d{{t}^{2}}}=2a-6bt=0\] Time, \[t=\frac{a}{3b}\]


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