2. Solved Papers
  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2010

  • question_answer
    The relation between time and displacement for two particles is given by \[{{y}_{1}}=0.06\,\sin \,2\pi (0.04t+{{\phi }_{1}})\]and \[{{y}_{2}}=0.03\,\sin \,2\pi (0.04t+{{\phi }_{2}})\] The ratio of the intensity of the waves, produced by the vibrations of the two particles will be

    A)  2 : 1                

    B)  1 : 2

    C)  4 : 1                

    D)  1 : 4

    Correct Answer: D

    Solution :

     Ratio of intensities\[\frac{{{I}_{1}}}{{{I}_{2}}}=\frac{A_{1}^{2}}{A_{2}^{2}}=\frac{{{(0.06)}^{2}}}{{{(0.03)}^{2}}}=\frac{4}{1}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner