RAJASTHAN ­ PET Rajasthan PET Solved Paper-2010

  • question_answer
    The solubility product of\[H{{g}_{2}}{{I}_{2}}\]is equal to

    A)  \[[Hg_{2}^{2+}][{{I}^{-}}]\]

    B)  \[[H{{g}^{2+}}][{{I}^{-}}]\]

    C)  \[[Hg_{2}^{2+}]{{[{{I}^{-}}]}^{2}}\]

    D)  \[[H{{g}^{2+}}]{{[{{I}^{-}}]}^{2}}\]

    Correct Answer: C

    Solution :

     \[H{{g}_{2}}{{I}_{2}}(s)Hg_{2}^{2+}+2{{I}^{-}}\] \[\therefore \] \[{{K}_{sp}}=[Hg_{2}^{2+}]{{[{{I}^{-}}]}^{2}}\]


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