2. Solved Papers
  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2010

  • question_answer
    The ratio of the difference in energy between the first and the second Bohr orbit to that between the second and the third Bohr orbit is

    A)  1/2               

    B)  1/3

    C)  4/9               

    D)  27/5

    Correct Answer: D

    Solution :

     \[\Delta E={{E}_{2}}-{{E}_{1}}=\frac{1312}{{{1}^{2}}}-\frac{1312}{{{2}^{2}}}=1312\left( \frac{3}{4} \right),\] \[{{E}_{3}}-{{E}_{2}}=\frac{1312}{{{2}^{2}}}-\frac{1312}{{{3}^{2}}}\] \[=1312\left( \frac{5}{36} \right)\] \[\therefore \] \[{{E}_{2}}-{{E}_{1}}:{{E}_{3}}-{{E}_{2}}=\frac{3}{4}:\frac{5}{36}=27:5\]


You need to login to perform this action.
You will be redirected in 3 sec spinner