A) \[0\]
B) \[\frac{\pi }{6}\]
C) \[\frac{\pi }{2}\]
D) \[\pi \]
Correct Answer: D
Solution :
amp\[(i\omega )+\]amp\[(i{{\omega }^{2}})=\]amp\[({{i}^{2}}{{\omega }^{3}})\] =amp\[(-1)\] \[=\pi \]
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