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  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2011

  • question_answer
    If half-life of a radioactive atom is 2.3 days then its decay constant would be

    A)  0.1              

    B)  0.2

    C)  0.3               

    D)  2.3

    Correct Answer: C

    Solution :

     \[\lambda =\frac{0.69}{T}\] \[\lambda =\frac{0.69}{2.3}\] \[\lambda =0.3\]


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