A) 93.75%
B) 75%
C) 25%
D) 6.25%
Correct Answer: A
Solution :
\[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] Here \[n=4\] \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{4}}\] \[\frac{N}{{{N}_{0}}}=\frac{1}{16}=6.25%\] Amount of decay\[=\frac{{{N}_{0}}-N}{{{N}_{0}}}=93.75%\]
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