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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2011

  • question_answer
    The emf of the cell involving following changes, \[Zn(s)+N{{i}^{2+}}(1M)\xrightarrow[{}]{{}}Z{{n}^{2+}}(1M)+Ni(s)\] is 0.5105 V. The standard emf of the cell is

    A)  0.540V        

    B)  0.4810V

    C)  0.5696V       

    D)  0.5105V

    Correct Answer: D

    Solution :

     \[{{E}_{cell}}=E_{cell}^{o}+\frac{0.059}{2}\log \frac{[N{{i}^{2+}}]}{[Z{{n}^{2+}}]}\] \[0.5105=E_{cell}^{o}+\frac{0.059}{2}\log \frac{1}{1}\] \[E_{cell}^{o}=0.5105\] \[(\because \log 1=0)\]


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