A) zero
B) \[\frac{h}{\sqrt{2\pi }}\]
C) \[\frac{h}{2\pi }\]
D) \[\frac{h}{2\sqrt{2\pi }}\]
Correct Answer: B
Solution :
Orbital angular momentum\[=\sqrt{1(1+1)}\frac{h}{2\pi }\] For p-orbital, \[l=1\] \[\therefore \]Orbital angular momentum\[=\sqrt{l(l+1)}\frac{h}{2\pi }\] \[=\frac{\sqrt{2}h}{2\pi }\] \[=\frac{h}{\sqrt{2}\pi }\]
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