A) \[Sb{{F}_{5}}\]
B) \[Mn{{F}_{3}}\]
C) \[KSb{{F}_{6}}\]
D) \[Mn{{F}_{4}}\]
Correct Answer: A
Solution :
Stronger Lewis acid,\[Sb{{F}_{5}}\]displaces the weaker one\[(Mn{{F}_{4}})\]from its salt.\[Mn{{F}_{4}}\]is unstable and readily decompose to give\[Mn{{F}_{3}}\]and fluorine. \[{{K}_{2}}Mn{{F}_{6}}+2Sb{{F}_{5}}\xrightarrow[{}]{{}}2Ksb{{F}_{5}}+\underset{unstable}{\mathop{Mn{{F}_{4}}}}\,\] \[2Mn{{F}_{4}}\xrightarrow[{}]{{}}2Mn{{F}_{3}}+{{F}_{2}}\]
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