A) \[{{H}_{3}}P{{O}_{3}}\]
B) \[{{H}_{3}}P{{O}_{2}}\]
C) \[{{H}_{4}}{{P}_{2}}{{O}_{7}}\]
D) \[{{H}_{3}}P{{O}_{4}}\]
Correct Answer: A
Solution :
\[PC{{l}_{3}}\]gives ortho phosphorus acid on reaction with\[{{H}_{2}}O\]. \[PC{{l}_{3}}+3H-O-H\xrightarrow[{}]{{}}\underset{\begin{smallmatrix} ortho\text{ }phosphorus \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,acid \end{smallmatrix}}{\mathop{{{H}_{3}}P{{O}_{3}}}}\,+3HCl\]
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