RAJASTHAN ­ PET Rajasthan PET Solved Paper-2011

  • question_answer
    Brown ring in the test of\[NO_{3}^{-}\]is formed due to the formation of

    A)  \[[Fe{{[{{H}_{2}}O]}_{5}}.NO]S{{O}_{4}}\]

    B)  \[[Fe{{[S{{O}_{4}}]}_{2}}.NO]{{H}_{2}}O\]

    C)  \[F{{e}_{2}}{{(S{{O}_{4}})}_{3}}.NO\]

    D)  None of the above

    Correct Answer: A

    Solution :

     Brown ring which indicates the presence of \[NO_{3}^{-}\]group in compound has chemical composition\[[Fe{{({{H}_{2}}O)}_{5}}NO]S{{O}_{4}}.\]. \[2NaN{{O}_{3}}+{{H}_{2}}S{{O}_{4}}\xrightarrow[{}]{{}}2NaHS{{O}_{4}}+2HN{{O}_{3}}\] \[2HN{{O}_{3}}+6FeS{{O}_{4}}+3{{H}_{2}}S{{O}_{4}}\xrightarrow[{}]{{}}\] \[3F{{e}_{2}}{{(S{{O}_{4}})}_{3}}+2NO+4{{H}_{2}}O\] \[[Fe{{({{H}_{2}}O)}_{6}}]S{{O}_{4}}+NO\xrightarrow[{}]{{}}\] \[[Fe{{({{H}_{2}}O)}_{5}}NO]S{{O}_{4}}+{{H}_{2}}O\]


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