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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2011

  • question_answer
    The maximum value of the function \[f(x)=\sin (x+\pi /6)+\cos (x+\pi /6)\] in the interval\[(0,\text{ }\pi /2)\]occurs at

    A)  \[\pi /12\]             

    B)  \[\pi /6\]

    C)  \[\pi /4\]              

    D)  \[\pi /3\]

    Correct Answer: A

    Solution :

     Maximum value of\[f(x)=\sqrt{2},\]when\[x+\pi /6=\pi /4\] i.e., when        \[x=\frac{\pi }{12}\]


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