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  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2011

  • question_answer
    \[\frac{d}{dx}\left\{ {{\sin }^{2}}{{\cot }^{-1}}\frac{1}{\sqrt{\frac{1+x}{1-x}}} \right\}\]

    A)  0              

    B)  \[-1/2\]

    C)  1/2             

    D)  \[-1\]

    Correct Answer: C

    Solution :

     Put \[x=cos\theta \Rightarrow \theta =co{{s}^{-1}}x\] \[\Rightarrow \] \[y=co{{s}^{2}}\theta /2\] \[=\frac{1+\cos \theta }{2}=\frac{1+x}{2}\Rightarrow \frac{dy}{dx}=1/2\]


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