A) 0
B) \[\sqrt{2}\]
C) \[-i\]
D) \[i\]
Correct Answer: B
Solution :
\[\sqrt{i}+\sqrt{-i}=\frac{1}{\sqrt{2}}(\sqrt{2i}+\sqrt{-2i})\] \[=\frac{1}{2}\{\sqrt{{{(1+i)}^{2}}}+\sqrt{{{(1-i)}^{2}}}\}\] \[=\frac{1}{\sqrt{2}}\{(1+i)+(1+i)\}\] \[=\sqrt{2}\]
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