A) 3.2 cm
B) 3.0 cm
C) 2.8 cm
D) 2.2 cm
Correct Answer: C
Solution :
The effective distance between the plates is decreased by\[\left( t-\frac{t}{k} \right)\]when a slab of thickness and dielectic constant k is introduced between the plates of a capacitor. To keep the capacitance of the capacitor unchanged, the plates of the capacitor will have to separate further by \[\left( t-\frac{t}{k} \right)\] \[\therefore \]The new distance between the plates \[=2+t-\frac{t}{k}\] Given, \[t=1\text{ }cm\] and \[k=5\] \[\therefore \]New distance \[=2+1-\frac{1}{5}=2.8\,cm\]
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