A) \[\frac{2}{3}\]
B) \[\frac{4}{3}\]
C) \[\frac{3}{4}\]
D) \[\frac{3}{2}\]
Correct Answer: B
Solution :
Given, \[{{\lambda }_{m}}=3.6\times {{10}^{-7}}m\] and \[{{\lambda }_{m}}'=4.8\times {{10}^{-7}}m\] According to Wein's displacement law \[{{\lambda }_{m}}T={{\lambda }_{m}}'T'\] (where T and T' be the temperature of two stars) \[\Rightarrow \] \[\frac{T}{T'}=\frac{{{\lambda }_{m}}'}{{{\lambda }_{m}}'}=\frac{4.8\times {{10}^{-7}}m}{3.6\times {{10}^{-7}}m}=\frac{4}{3}\]
You need to login to perform this action.
You will be redirected in
3 sec
