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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2012

  • question_answer
    If\[{{I}_{A}},{{K}_{A}}\]and\[{{I}_{B}},{{K}_{B}}\]are the moments of interia and kinetic energies of two freely rotating bodies A and B respectively, such that\[{{I}_{A}}>{{I}_{B}}\]and their angular mements are equal, then

    A)  \[{{K}_{A}}<{{K}_{B}}\]

    B)  \[{{K}_{A}}>{{K}_{B}}\]

    C)  \[{{K}_{A}}={{K}_{B}}\]

    D)  \[{{K}_{A}}=2{{K}_{B}}\]

    Correct Answer: A

    Solution :

     We know that, \[K=\frac{{{L}^{2}}}{2I}\] Given,        \[{{L}_{A}}={{L}_{B}}\] and           \[{{I}_{A}}>{{I}_{B}}\] \[\therefore \] \[\frac{{{K}_{A}}}{{{K}_{B}}}=\frac{{{I}_{B}}}{{{I}_{A}}}<1\] \[\Rightarrow \] \[{{K}_{A}}<{{K}_{B}}\]


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