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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2012

  • question_answer
    The smallest positive integer n for which\[{{(1+i)}^{2n}}={{(1-i)}^{2n}}\]is

    A)  1        

    B)  2

    C)  3    

    D)  4

    Correct Answer: B

    Solution :

    Given that, \[{{(1+i)}^{2n}}={{(1-i)}^{2n}}\] \[\Rightarrow \] \[{{2}^{n}}{{i}^{n}}={{2}^{n}}{{(-1)}^{n}}{{i}^{n}}\] \[\Rightarrow \] \[(1)={{(-1)}^{n}}\] \[\therefore \]The smallest value of n is 2.


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