RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    A hammer of mass 1 kg having speed of\[50\text{ }m/s,\] hit a iron nail of mass \[200gm\]. If specific heat of iron is \[0.105cal/g{{m}^{o}}C\]and half the energy is converted into heat, the raise in temperature of nail is:

    A)  \[{{7.1}^{o}}C\]               

    B)                         \[{{9.2}^{o}}C\]               

    C)         \[{{10.5}^{o}}C\]            

    D)         \[{{12.1}^{o}}C\]

    Correct Answer: A

    Solution :

    According to law of conservation heat. \[ms\,\Delta t=\frac{1}{2}\left( \frac{1}{2}m{{\upsilon }^{2}} \right)\times \frac{1}{4.2}\]                 \[\,\Delta t=\frac{1\times 50\times 50}{0.2\times 4\times 4.2\times 0.105\times {{10}^{3}}}={{7.1}^{o}}C\]


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