A) zero
B) \[\frac{1}{2}\]
C) \[\frac{F}{4}\]
D) \[\frac{F}{8}\]
Correct Answer: D
Solution :
On axial line of a dipole, force \[F\propto \frac{1}{{{r}^{3}}}\] \[\frac{{{F}_{1}}}{{{F}_{2}}}={{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{3}}={{\left( \frac{2d}{d} \right)}^{3}}\] \[{{F}_{2}}={{F}_{1}}/8\] \[\Rightarrow \]\[{{F}_{2}}=F/8\]
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