A) \[1.25\,volt\]
B) \[2.5\,volt\]
C) \[5\,volt\]
D) \[10\,volt\]
Correct Answer: B
Solution :
Voltage gain \[A=\frac{\mu {{R}_{L}}}{{{R}_{P}}+{{R}_{L}}}\] \[=\frac{25\times 10\times {{10}^{3}}}{40\times {{10}^{3}}+10\times {{10}^{3}}}=5\] \[\frac{{{V}_{out}}}{{{V}_{in}}}=A\] \[\therefore \] \[{{V}_{out}}=A\,{{V}_{in}}\] \[=5\times 0.5=2.5volt\]
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