RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    Moment of inertia of a fan is\[0.06kg-{{m}^{2}}\]. If its angular speed is increased from 0 to 5 revolution/sec. Then its maximum angular momentum in M.K.S. unit is:

    A)  \[0.3\,\pi \]

    B)                                         \[0.6\,\pi \]       

    C)        \[\frac{0.03}{\,\pi }\]     

    D)         \[\frac{0.6}{\,\pi }\]

    Correct Answer: B

    Solution :

    Angular momentum \[J=I\omega \] \[J=I.\,\,2\pi n=0.6\times 2\pi \times 5=0.6\pi \]


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