RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    Two sources of sound of same frequency are situated at a distance 1 metre apart. An observer is moving parallel to line joining them at a distance 10 metre. If distance  between   two  consecutive an tinode is observed to be \[1.1\] metre, then    frequency    of   source   is (\[\upsilon \] = 300 m/sec):

    A)  \[1000\,Hz\]                     

    B)                         \[3000\,Hz\]                     

    C)         \[3500\,Hz\]                     

    D)         \[4000\,Hz\]

    Correct Answer: B

    Solution :

    Frequency \[n=\frac{\upsilon }{\lambda }=\frac{330}{1.1}=3000Hz\]


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