RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    Mean mass of an element is 39.1 amu, The masses of its isotopes are 39, 40, 41 amu. If the abundance isotope of 40 amu is 0.012%, then relative abundance of other two is:

    A)  93.7, 6.233         

    B)         90.237, 8.751    

    C)                         93.073, 6.915    

    D)         91.387, 8.603

    Correct Answer: C

    Solution :

                    Not available


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