RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    Length of a simple pendulum is \[I\]and its maximum angular displacement is \[\theta \] then its maximum K.E. is :

    A) \[mgl\,\sin \,\theta \]                   

    B)                        \[mgl(1+\,\sin \,\theta )\]           

    C)                         \[mgl(1+\,\cos \,\theta )\]         

    D)        \[mgl(1-\,\cos \,\theta )\]

    Correct Answer: D

    Solution :

    \[h=l-I\cos \theta =l(1-\cos \theta )\] From law of conservation of momentum \[\frac{1}{2}m{{\upsilon }^{2}}=mgh=mgl\,(1-\cos \theta )\]


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