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  3. RAJASTHAN PMT

RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    Extension in length of a spring is 12 cm, when 5 kg mass is suspended on it. If spring oscillate vertically, then its time period is:

    A)  0.7 sec

    B)         0.9 sec                

    C)         1.1 sec                

    D)         1.4 sec

    Correct Answer: A

    Solution :

                    Time period \[T=2\pi \sqrt{\frac{x}{g}}\] \[=2\pi \sqrt{\frac{12\times {{10}^{-2}}}{9.8}}=0.7\sec \]              


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