A) \[C{{H}_{3}}OH\]
B) \[C{{H}_{3}}C{{H}_{2}}OH\]
C) \[C{{H}_{3}}COOH\]
D) \[CH\equiv CH\]
Correct Answer: A
Solution :
\[HCHO+HCHO\xrightarrow[NaOH]{+40%}\] \[\underset{\begin{smallmatrix} Methyl\,\,alcohol \\ (reductive\,product) \end{smallmatrix}}{\mathop{C{{H}_{3}}OH+}}\,\underset{\begin{smallmatrix} Sodium\,formate \\ (oxidative\,product) \end{smallmatrix}}{\mathop{H-COONa}}\,\]
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