A) \[C{{H}_{3}}COOH\]
B) \[C{{H}_{3}}C{{H}_{2}}OH\]
C) \[C{{H}_{3}}CHO\]
D) \[HCOOH\]
Correct Answer: B
Solution :
\[H-\underset{H}{\mathop{\underset{|}{\mathop{C}}\,}}\,=O+C{{H}_{3}}Mg\,Br\xrightarrow{{}}\] \[H-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{\overset{H}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-Mg\,OBr\xrightarrow{H.\,OH/{{H}^{+}}}\] \[C{{H}_{3}}C{{H}_{2}}OH+Mg(OH)Br\]
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