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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    What is the pH value of \[40ml\text{ }0.10M\,HCl\] solution combind with \[10ml\text{ }0.45M\] \[NaOH\]solution?

    A)  \[12\]                  

    B)         \[8\]    

    C)  \[10\]                  

    D)         \[6\]

    Correct Answer: A

    Solution :

    Milli mole of \[HCl=40\times 0.10=4\text{ }mole\] Milli mole of \[NaOH=0.45\times 10=4.5\text{ }mole\] Balanced mole \[=4.5-4=0.5\] Total volume \[[O{{H}^{-}}]=\frac{0.5}{500}={{10}^{-2}}\]                 \[pOH=2\]                 \[pH=14-pOH=14-2=12\]


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